Starter solenoid issue

[Drako750]

Ok. I'm now working on my wiring. Using a wiring harness from vintagecb750.com for my '74 cb750k4. For me. Looks like I'll be chopping it up an not using a lot of the wires in it. I've looked at diagrams of the solenoid. One terminal goes to the starter motor cable coming out of the case. The other to the positive terminal of the battery. Check. What do the two wires that come out of the solenoid go to though. Most diagrams show one yellow/red wire and a green/reddish wire. First color is the dominant color. The other a stripe. I've seen one wire going to the key ignition switch. The other. Donno. But my ignition key has a plug on it that plugs into my harness. Soooo. What do I do? Any help. Better/more complete diagram pix. Something. I'm not very good at electrical things. So dumb it down for me please.

[TOOLS1]

One wire comes from the starter button to activate it, by completing a grounded circuit. The other is "hot" to the solenoid.
TOOLS

[Drako750]

Ok. So the hot wire. What do you mean by hot. What does it connect to to make it hot?

Sent from my iPhone

On Oct 3, 2014, at 8:08 PM, "TOOLS1 [via Honda CB750'S]" <[hidden email]> wrote:

One wire comes from the starter button to activate it, by completing a grounded circuit. The other is "hot" to the solenoid.
TOOLS

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NAML

[Drako750]

This is they type of solenoid that I have. Found a picture.

[TOOLS1]

The "hot" wire has electricity coming to it from the ignition switch. The other wire goes to the starter button. When you press the starter button, it grounds the circuit, and makes the solenoid activate.
TOOLS

[LukeM]

OK, here's how a solenoid works:

It is essentially a large current relay, controlled by a low current coil.

Loop A, if you will, is the low current side.  It takes V+ from your battery or starter switch in this case, and connects it to one side, and the other is connected to ground.  When you connect V+ to the top, it energizes a small coil, which closes the contacts on the high current side (loop B).  When the high current contacts close, the battery connection is directly connected to the + post on the battery.  When you release the starter switch, the coil in loop A de-energizes, and a small spring opens the high current contacts.  Current is then no longer flowing along the high current side (loop B)

This is done so the 15-20 amps the starter needs isn't connected via a small current switch. If you DO connect this amount of current over such a switch, the contacts will pit out and eventually stop working.

I hope this helps.
Luke M